https://www.acmicpc.net/problem/14954
문제
Consider the following function f defined for any natural number n:
f(n) is the number obtained by summing up the squares of the digits of n in decimal (or base-ten).
If n = 19, for example, then f(19) = 82 because 12 + 92 = 82.
Repeatedly applying this function f, some natural numbers eventually become 1. Such numbers are called happy numbers. For example, 19 is a happy number, because repeatedly applying function f to 19 results in:
- f(19) = 12 + 92 = 82
- f(82) = 82 + 22 = 68
- f(68) = 62 + 82 = 100
- f(100) = 12 + 02 + 02 = 1
However, not all natural numbers are happy. You could try 5 and you will see that 5 is not a happy number. If n is not a happy number, it has been proved by mathematicians that repeatedly applying function f to n reaches the following cycle:
4 → 16 → 37 → 58 → 89 → 145 → 42 → 20 → 4.
Write a program that decides if a given natural number n is a happy number or not.
입력
Your program is to read from standard input. The input consists of a single line that contains an integer, n (1 ≤ n ≤ 1,000,000,000)
출력
Your program is to write to standard output. Print exactly one line. If the given number n is a happy number, print out HAPPY; otherwise, print out UNHAPPY.
풀이
답안코드
#include <iostream>
using namespace std;
#define MAXN ((int)1e3)
int N;
int used[MAXN + 10];
void InputData() {
cin >> N;
}
int cal(int number) {
int sol = 0;
int tmp = number;
while (number != 0) {
tmp = (number % 10);
sol += (tmp * tmp);
number /= 10;
}
return sol;
}
void Solve(int num) {
while (1)
{
num = cal(num);
if (num == 1) {
cout << "HAPPY";
return;
}
else if (used[num] == 1) break;
used[num] = 1;
}
cout << "UNHAPPY";
}
int main() {
InputData();
Solve(N);
return 0;
}
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